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2.7x^2=2
We move all terms to the left:
2.7x^2-(2)=0
a = 2.7; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·2.7·(-2)
Δ = 21.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{21.6}}{2*2.7}=\frac{0-\sqrt{21.6}}{5.4} =-\frac{\sqrt{}}{5.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{21.6}}{2*2.7}=\frac{0+\sqrt{21.6}}{5.4} =\frac{\sqrt{}}{5.4} $
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